-50x^2+2500x-20000=0

Solution for -50x^2+2500x-20000=0 equation:

-50x^2+2500x-20000=0

a = -50; b = 2500; c = -20000;
Δ = b2-4ac
Δ = 25002-4·(-50)·(-20000)
Δ = 2250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2250000}=1500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2500)-1500}{2*-50}=\frac{-4000}{-100}
=+40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2500)+1500}{2*-50}=\frac{-1000}{-100}
=+10
$